By: Daniel Shiffman

Daniel Shiffman — Thu, 11 Mar 2010 17:16:57 +0000

1. Yes, technically speaking, it would be better for me to have written:

  for (int i = 0; i < randomCounts.length; i++ ) {
    randomCounts[i] = 0;
  }

It's always a good idea to initialize. Since the default value for a float is 0, the code works without it anyway. 2. I'm not seeing this. When I add:

  println(randomCounts[0]);

to the end of draw(), the output I see is 0.0, 1.0, 2.0, etc.

By: P3HO

P3HO — Wed, 10 Mar 2010 19:08:53 +0000

1.
In this example, where is the part of initializing an array “radomCounts”?
I think there is no initializing and randomCounts[0] ~ randomCounts[19] have same default value “0.00″… right? (I’m confusing about array’s data have default value when there’s no initializing start values of array’s data.)

2.
I tried to ” print(randomCounts[0]); “, and the value of randomCounts[0] increased by 0.01, not by 1 that the value I expected..
I guess, according to ” randomCounts[ index ] ++; “, the value of randomCounts[0] increase by 1.
I changed ” randomCounts[index]++ ” to ” randomCounts[index] += 3; “, and the value of randomCounts[0] increased by 0.03, not by 3 that I expected… Explain me, please…;-)

Comments on: Example 13-2: Random Number Distribution

By: Daniel Shiffman

By: P3HO