Comments on: Example 15-7: Displaying the Pixels of an Image

By: Anonymous

Anonymous — Tue, 03 Jan 2012 18:00:00 +0000

Make sure your image is the same dimensions as your Processing window, i.e.

size(640,480);

your image should be 640×480

By: HANDIKA ERANDO

HANDIKA ERANDO — Thu, 22 Dec 2011 06:20:00 +0000

for (int y = 0; y < height; y++ ) {
for (int x = 0; x < width; x++ ) {
int loc = x + y*width; int displayLoc = x + y*width; int imageLoc = x + y*img.width; pixels[displayLoc] = img.pixels[imageLoc];
float r = red(img.pixels [loc]);
float g = green(img.pixels[loc]);
float b = blue(img.pixels[loc]);

pixels[loc] = color(r,g,b);
}
}Where i must insert that code…i am already trying implements that code like above…but in row float r … blabla error in arrayindexoutofbound exception 40000

By: random

random — Fri, 11 Mar 2011 20:09:00 +0000

Thank you very very much Daniel!!! Now is clear…
P.S: thank for your quick response.

By: Anonymous

Anonymous — Fri, 11 Mar 2011 02:16:00 +0000

Exactly, you would say:

int displayLoc = x + y*width;
int imageLoc = x + y*img.width;
pixels[displayLoc] = img.pixels[imageLoc];

By: random

random — Fri, 11 Mar 2011 02:00:00 +0000

If the image source has not the same dimension of the display area… where i put “int imageLoc = x + y*img.width;”, and where “int displayLoc = x + y*width;”