Comments on: Exercise 4-6: Zoog shakes horizontally

By: Berthalaban

Berthalaban — Mon, 30 Jan 2012 05:47:00 +0000

Zoog would still shake horizontally if you wrote ‘zoogX=random(5)’

But the answer is ‘=zoogX+random(-5,5)’
because first,
you would want zoog to start shaking in the middle of the canvas
(this is done by adding zoogX in the equation again)

and then second,
you would want to control the boundary of the random number.
(from -5 to 5)

By: stani

stani — Fri, 07 Oct 2011 11:07:00 +0000

This is what I tried…obviously not correct :

zoogX = random(zoogY-zoogX);

By: Anonymous

Anonymous — Fri, 18 Mar 2011 00:44:00 +0000

zoogX is the variable that controls the horizontal position of Zoog. If you change zoogX by a random value (positive or negative) every frame, Zoog’s horizontal location will appear to shake (randomly moving left and right).

By: flor

flor — Tue, 15 Mar 2011 15:29:00 +0000

Why the solution of this exercise is zoogX = zoogX + random(-5,5);?

By: Daniel Shiffman

Daniel Shiffman — Mon, 15 Feb 2010 15:15:48 +0000

Thanks for the comment. For some reason I made this example (and exercise) have Zoog’s legs attached to the bottom of the window. But there’s no particular reason for this so your alternative is a good one!

By: Nuno Araujo

Nuno Araujo — Fri, 12 Feb 2010 18:29:41 +0000

There’s a small error on the code of the answer, in is legs…
It says:
// Draw Zoog’s legs
stroke(150);
line(zoogX-10,zoogY+50,zoogX-10,height);
line(zoogX+10,zoogY+50,zoogX+10,height);

I belive it should be something like:
line(zoogX-10,zoogY+50,zoogX-15,zoogY+65);
line(zoogX+10,zoogY+50,zoogX+15,zoogY+65);

PS: Thanks for this exercises!